Unit Converter

Level 1

Chapter 1: Python Setup for Petroleum Engineering

descriptionProblem

Convert these oilfield values to SI units and store each result in the indicated variable:

Pressure: 4,800 psi → kPa (1 psi = 6.89476 kPa) → p_kpa
Depth: 9,200 ft → m (1 ft = 0.3048 m) → depth_m
Volume: 15,000 bbl → m³ (1 bbl = 0.158987 m³) → vol_m3
Density: 11.6 ppg → kg/m³ (1 ppg = 119.826 kg/m³) → rho_kgm3
API gravity: 35° API → specific gravity using

$SG = 141.5 / (API + 131.5)$ → sg. Verify your result is approximately 0.8498.

Bonus. Convert the specific gravity back to API using $API = 141.5 / SG - 131.5$ and store it in api_back. Confirm you recover the original 35° within rounding tolerance.

lightbulbHints (0/4)

Stuck? Reveal hints one at a time — they progress from nudge to near-solution.

codeYour solution

main.py

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Try solving it yourself first — the hints walk you through it. The solution below is one valid approach; yours may differ and still be correct.

p_kpa    = 4800 * 6.89476
depth_m  = 9200 * 0.3048
vol_m3   = 15000 * 0.158987
rho_kgm3 = 11.6 * 119.826
sg       = 141.5 / (35 + 131.5)
api_back = 141.5 / sg - 131.5

print(f"4800 psi  = {p_kpa:.1f} kPa")
print(f"9200 ft   = {depth_m:.2f} m")
print(f"15000 bbl = {vol_m3:.2f} m^3")
print(f"11.6 ppg  = {rho_kgm3:.2f} kg/m^3")
print(f"35 API    = {sg:.4f} SG")
print(f"SG → API  = {api_back:.4f}  (should be 35)")

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1.2 Mud Weight Window

1.4 Bottomhole Pressure Report

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